Question

in a gp 6th term is 192 and 8th term is 768. find the 10th term

Answer 1

Answer:

3072

Step-by-step explanation:

suppose the 1st term of the gp is = a

    ar^5 = 192     ;           ar^7  =  768

or,    a   = 192/r^5   ; or,     a   = 768/r^7

∴  192/r^5 = 768/r^7

or,      r²     =   768/192 = 4

or,      r      =   2

∴ a = 192/2^5 = 192/32 = 6

the 10 th term is = ar^9 = (6×2^9) = (6 × 512) = 3072