Question

In a GP (Geometric progression) which is 20,30,40,50...70 find their sum of their 74 term

Answer 1

Answer:

28490..................

Answer 2

Answer:

Marj as brainliest please

Step-by-step explanation:

$a = 20 \\ r = \frac{30}{20} = \frac{3}{2} \\ sum = \frac{a( {r}^{n} - 1) }{ {r} - 1 } \\ sum = \frac{20( { \frac{3}{2} })^{74} - 1 }{ \frac{3}{2} - 1 } \\ sum = 4.3 \times {10}^{14}$

but the series is not a Geometric Progression