in a group of students to study chemistry 15 study statistics 11th study physics for study chemistry only 7 study statistics only three studies statistics and physics only and one study chemistry and Statistics onley how many students study all these objects.
Answers
Given , N=55,n(M)=23,n(P)=24,n(C)=19,n(M∩P)=12,n(P∩C)=7,n(M∩C)=9,n(M∩P∩C)=4
Now, number of students studying only Mathematics
n(M∩P ′ ∩C ′
)=n(M)−n(M∩P)−n(M∩C)+n(M∩P∩C) (by Venn diagram)
=23−9−12+4=6
Now, number of students studying only Physics
n(P∩M ′ ∩C ′
)=n(P)−n(P∩M)−n(P∩C)+n(P∩M∩C) (by Venn diagram)
=24−12−7+4=9
Now, number of students studying only Chemistry
n(C∩M ′ ∩P ′
)=n(C)−n(C∩M)−n(C∩P)+n(M∩P∩C) (by Venn diagram)
=19−9−7+4=7
So, the number of people who study exactly one of the three subjects =6+9+7=22
Answer:
in a group of students to study chemistry 15 study statistics 11th study physics for study chemistry only 7 study statistics only three studies statistics and physics only and one study chemistry and Statistics onley how many students study all these objects.
Step-by-step explanation:
in a group of students to study chemistry 15 study statistics 11th study physics for study chemistry only 7 study statistics only three studies statistics and physics only and one study chemistry and Statistics onley how many students study all these objects.