In a HCL molecule the separation between the nuclei of two atoms is 1.27x10∧-10m. Find the location of center of mass of the molecule, if the Cl atom is 35.5 times as massive as a hydrogen atom.
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9
treating them as point masses along the separation line between the two:
Let the position of center of mass be x meters from hydrogen atom. Let center of mass be at position 0.
Mass of hydrogen * distance of H atom from center of mass + Mass of chlorine * distance of chlorine atom from center of mass = 0
1 * (- X - 0) + 35.5 * (1.27 * 10^-10 - X - 0) = 0
- X + 35.5 * 1.27 * 10^-10 - 35.5 X = 0
36.6 X = 35.5 * 1.27 * 10^-10
X = 3.47 * 10^-12 m
Center of mass is 1.23 * 10^-10 meters away from hydrogen atom.
Let the position of center of mass be x meters from hydrogen atom. Let center of mass be at position 0.
Mass of hydrogen * distance of H atom from center of mass + Mass of chlorine * distance of chlorine atom from center of mass = 0
1 * (- X - 0) + 35.5 * (1.27 * 10^-10 - X - 0) = 0
- X + 35.5 * 1.27 * 10^-10 - 35.5 X = 0
36.6 X = 35.5 * 1.27 * 10^-10
X = 3.47 * 10^-12 m
Center of mass is 1.23 * 10^-10 meters away from hydrogen atom.
Answered by
2
consider h2 at origin and cl2 at 1.27 from origin on x axis
coordinates of h2-(0,0)
coordinates of cl-2(1.27,0) (10^-10m=1A)
Xcm=m1×0+35.5×1.27÷1+35.5
Xcm=45.085÷36.5
Xcm=1.24 from h-end
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