in a home count of bacteria in a certain area is increasing at the rate of 2..5%per day.find the the bacteria at the end of 2days if the count was initially 64000.
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64000( 1 + 2.5/ 100)^ 2
64000(41/40)^2
64000*41/40 * 41/40
= 67240
64000(41/40)^2
64000*41/40 * 41/40
= 67240
umarabdullah01:
so so thanks brother
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