In a hostel it takes ₹1800 to keep 50 children for 8 weeks . For what length of time did the cost of keeping 90 children amount to ₹21060?
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Use the unitary method.
8 weeks = 8×7 days= 56 days.
To keep 1 child for 56 days, cost= 1800÷50 = Rs. 36
Therefore, to keep 1 child for 1 day, cost= 36/56 ...................{1}
Now, to keep 90 children for 1 day, cost= 90×36/56...............................{2}
Let the number of days be x.
Then,
21060= 90×36/56×x
21060/90 ×56/36 =x {now do the division and multiplication}
=364 = x
Hence 90 children can be kept for 364 days in the hostel for rupees 21060.
I hope this helps.
8 weeks = 8×7 days= 56 days.
To keep 1 child for 56 days, cost= 1800÷50 = Rs. 36
Therefore, to keep 1 child for 1 day, cost= 36/56 ...................{1}
Now, to keep 90 children for 1 day, cost= 90×36/56...............................{2}
Let the number of days be x.
Then,
21060= 90×36/56×x
21060/90 ×56/36 =x {now do the division and multiplication}
=364 = x
Hence 90 children can be kept for 364 days in the hostel for rupees 21060.
I hope this helps.
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