Question

In a hot water heating system there is a cylindrical pipe of length 28 M and diameter 5 cm. Find the total radiating surface in the system?

Answer 1

in this question we have to find the TSA of cylinder...
given that -length =28m,diameter =5cm
now
TSA of cylinder=
$2pirh$
putting aal the values in formula
=2×22/7×5/2×28=22/7×5×28=22/7×140=
22×20=440cm square.........
I hope it's help u.......

Answer 2

$\huge\mathbb\pink{Hey \: Mate!!}$

${\huge{\red{\underline{\overline{\mathit{\red{ANSWER↓}}}}}}}$

h = 28m

2r=5cm

$\therefore$ r = $\large\dfrac{5}{2}$ cm = $\large\dfrac{5}{2×100}$

= $\large\dfrac{5}{200}$ m = $\large\dfrac{1}{40}$ m

$\therefore$ Total radiating surface in the system

= ${\small{\boxed{\sf{\pink{2πrh}}}}}$

= 2 × $\large\dfrac{27}{7}$ × $\large\dfrac{1}{40}$ × 28 = ${\underline{\underline{4.4m²}}}$

The area of the radiating surface of system is 4.4 m²

$\large\underline\mathbb\red{HOPE \: THIS \: HELPS \: U}$

$\large\fbox\colorbox{pink}{Mark \: as Brainliest}$