In a house 2 bulbs of 50w each are used for 5 hours per day and 2 fans of 70W each are uses for 10 hours per day. Calculate how many units are consumed in 30 days.
Answers
1 Kilowatt of power for 1 hour then you consume 1 unit.
Total power consumption=
Bulbs:(2*50) = 100W . 100W * 5hr =500WHr
Fan : (2* 70) = 140W . 140W * 10hrs= 1400WHr
In total : 1900W Hr per day
IN one month : 1900 * 30 = 57000WHr
No of units consumed is : 57000/1000 = 57 units
2 Bulbs and 2 fans are operatied 5 and 10 hr respectively.
2 bulb are 50 W each
we will take 1 bulb first
N = Pt÷1000-Wh/unit
= 50*150÷1000
= 7.5 units.
Therefore, 1 bulb takes 7.5 units.
So, 2 bulbs will be = 7.5 + 7.5 = 15 units.
Therefore, 2 bulbs of 50W take 15 units in a month.
Now, we shall take 1 fan
N = Pt÷1000-Wh/unit
= 70*300÷1000
= 21 units
Therefore, one fan takes 21 unit
So, 2 fans of 70W will be
= 21 + 21
= 42 Units.
Therefore, 2 fans of 70W take 42 units.
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