In a house 460 watt electric bulb are lighted for 2 hour and 200 ward bulb are lighted 4 hours everyday calculate the energy consumed in the house for the month of May also find out the energy course if energy force is 3.50 per kilo watt
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Secondary School Physics 5 points
In a house two 60 Watt bulbs are lighted for 4 hours, and three 100 watt bulbs for 5 hours everyday. calculate the electric energy consumed in 30 days
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justice2
59.4 kj
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THE BRAINLIEST ANSWER!
Bulb1 are 2 n number
Power (P1) = 60W
time (t1) = 4 hr
Energy consumed in one day (W1) = P1 x t1 x 2 = 60W x 4h x 2 = 480Wh
bulb2 are 3 in number
Power (P2) = 100W
time (t2) = 5 hr
Energy consumed in one day (W2) = P2 x t2 = 100W x 5h x 3 = 1500Wh
therefore, electric energy consumed in one day = W1 + W2 = 480+1500 = 1980Wh
electric energy consumed in 30 days = 1980 x 30 = 59400 Wh = 59.4 kWh
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