Question

in a house 60 watt electric bulb are lighted for 4 hours and 300 words ball for 5 hours everyday calculate the electrical energy consumed in 30 days​

Answer 1

Answer:

Bulb1 are 2 n number

Power (P1) = 60W

time (t1) = 4 hr

Energy consumed in one day (W1) = P1 x t1 x 2 = 60W x 4h x 2 = 480Wh

bulb2 are 3 in number

Power (P2) = 100W

time (t2) = 5 hr

Energy consumed in one day (W2) = P2 x t2 = 100W x 5h x 3 = 1500Wh

therefore, electric energy consumed in one day = W1 + W2 = 480+1500 =  1980Wh

electric energy consumed in 30 days = 1980 x 30 = 59400 Wh = 59.4 kWh

Explanation:

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Answer 2

Answer:

52.2 Kwh

Explanation:

Given:

• 60 watt bulb is lighted for 4 hours
• 300 watt bulb is lighted for 5 hours

To find:

• Electrical energy consumed in 30 days by 60 watt bulb and the 300 watt bulb

60 watt bulb:

Power = 60 watt

Time = 4 hours

Number of bulbs = 1

Energy consumed = power×Time×Number of bulbs

Energy consumed = 60×4×1= 240 Watt hours

300 watt bulb:

Power = 300 watt

Time = 5 hours

Number of bulbs = 1

Energy consumed = Power×Time×Number of bulbs

Energy consumed = 300×5×1= 1500 Watt hours

Total electrical energy consumed = 240Wh+1500Wh

Total electrical energy consumed = 1740Wh

Electrical energy consumed in 30 days = 1740×30

Electrical energy consumed in 30 days = 52,200 Wh = 52.2 Kwh

The electrical energy consumed is equal to 52.2 Kwh