In a house, electric kettle of 1500 W is used everyday for 45 minutes, to boil water. Find the amount payable per month (30 days) for usage of this, if cost per unit is Rs. 3.25
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Given conditions ⇒
Power = 1500 W.
= 1.5 kW.
The kettle of Power 1.5 kW is used daily for 45 minutes.
Time = 45 minutes.
Now, Total time in 30 Days = 45 × 30 minutes.
= 45 × 30/60
= 22.5 hours.
Now, Total amount of the Energy used = Power in kW × Time in hrs.
= 1.5 × 22.5
= 33.75 kWh.
Now, Total cost of this Energy = 33.75 × Cost of 1 unit.
= 33.75 × 3.25
= Rs. 109.6875
≈ Rs. 110
Hence, the cost is Rs.110.
Hope it helps.
Power = 1500 W.
= 1.5 kW.
The kettle of Power 1.5 kW is used daily for 45 minutes.
Time = 45 minutes.
Now, Total time in 30 Days = 45 × 30 minutes.
= 45 × 30/60
= 22.5 hours.
Now, Total amount of the Energy used = Power in kW × Time in hrs.
= 1.5 × 22.5
= 33.75 kWh.
Now, Total cost of this Energy = 33.75 × Cost of 1 unit.
= 33.75 × 3.25
= Rs. 109.6875
≈ Rs. 110
Hence, the cost is Rs.110.
Hope it helps.
Answered by
0
Answer:
the cost is 110
Explanation:
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