Question

In a house two 60 Watt bulbs are lighted for 4 hours, and three 100 watt bulbs for 5 hours everyday. calculate the electric energy consumed in 30 days

Answer 1

bulb1 are 2 n number
Power (P1) = 60W
time (t1) = 4 hr
Energy consumed in one day (W1) = P1 x t1 x 2 = 60W x 4h x 2 = 480Wh


bulb2 are 3 in number
Power (P2) = 100W
time (t2) = 5 hr
Energy consumed in one day (W2) = P2 x t2 = 100W x 5h x 3 = 1500Wh



therefore, electric energy consumed in one day = W1 + W2 = 480+1500 =  1980Wh
electric energy consumed in 30 days = 1980 x 30 = 59400 Wh = 59.4 kWh

Answer 2

Hlo friend.. Cutiepie Here...

Here is ur answer :

Bulbs = 2

Power = 60 W

1 kW = 1000 W

1 W = 1 / 1000 kW

60W = 60 / 1000 kW

Time = 4 hours

Energy = Power × time


$\frac{60}{1000} \times 4$


Energy of 1 bulb = 6/25 kWh = 0.24 kWh


Energy of 2 bulbs in one day

$= 0.24 \: \times 2$


= 0.48 kWh

__________________________________

Bulbs = 3

Power = 100 W = 0.1 kW

Time = 5 hours

Energy = Power × time

= 0.1 × 5

= 0.5 kWh

Energy of 1 bulb = 0.5 kWh

Energy of 3 bulbs in one day

= 3 × 0.5 = 1.5 kWh

___________________________

Total energy used in 1 day

= 0.48 + 1.5

= 1.98 kWh

Electric energy used in 30 days

= 30 × 1.98

= 59.4 kWh

_____________________________

HOPE IT HELPS YOU ..

REGARDS
@sunita