In a hydraulic jack as shown mass of the car w=800 kg a1 10 cm2
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The question seems to be incomplete. Here is the complete question:
In a hydraulic jack as shown mass of the car W =800 kg, A₁ 10 cm² A₂ = 10m². The minimum force required to lift the car is:
A) 1 N
B) 0.8N
C) 8N
D) 16N
Solution:
The answer to this question is B) 0.8N
F₁/A₁ = F₂/A₂
F/10 = 8000/ 10 x 10⁴
= F = 0.8 N
If there is any confusion please leave a comment below.
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