Question

In A hydraulic lift the force applied on to smaller cylinder of area A1 is F1 .if the area of the larger cylinder is A2 the maximum weight that can be lifted is

Answer 1

Answer:

By Pascal's law:-

P1 = P2

F1/A1 = F2/A2

F2 =( A2 × F1 )/A1

Answer 2

The maximum weight that can be lift is F₁ A₂/ A₁

Given, The area of the larger cylinder of the hydraulic lift = A₂

           The area of the smaller cylinder of the hydraulic lift = A₁

            Force applied on the smaller cylinder =  F₁

Let, the force applied on the larger cylinder = F₂

According to Pascal's Law,

F₁ / A₁ = F₂ / A₂

⇒ F₂ = F₁ A₂/ A₁

Now, suppose the maximum weight that can be lifted = W

                                            = mg [m = mass, g = Acceleration due to gravity] = Force applied on the larger cylinder

= F₂

= F₁ A₂/ A₁

So, the maximum weight that can be lifted is F₁ A₂/ A₁ .