in a hydraulic machine, a force of 2N is applied on the piston of area of cross section 10 cm2. what force is obtained on its piston of area of cross section 100 cm2.
Answers
Answered by
72
According to the pascal's law the increase in pressure is same at all the points when any force is applied
converting the area in cm2 to m2 by diving with10*4
2N÷10/10*4=F÷100/10*4
F=20N
converting the area in cm2 to m2 by diving with10*4
2N÷10/10*4=F÷100/10*4
F=20N
PowerHouse41:
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Answered by
96
Explanation:
f =2N
area =10cm²
pressure =f/a
= 2/10
=1/5
next, area =100cm²
pressure =f/a
= f/100
ATQ
f/100=1/5
f =1/5*100 =20N
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