Question

In a hydraulic machine the two pistons are in the ratio of 1:10. what force is needed on the narrow piston to overcome the force of 100N on the wider piston?

Answer 1

Answer:

may be helpful if you know what is Pascal's law

In a hydraulic machine the two pistons are in the ratio of 1:10. what force is needed on the narrow piston to overcome the force of 100N on the wider

Explanation:

According to the pascal's law the increase in pressure is same at all the points when any force is applied

converting the area in cm2 to m2 by diving with10*4

2N÷10/10*4=F÷100/10*4

F=20N

Answer 2

Answer:

In an Hydraulic machine,

Explanation:

Given

Area of cross-section = 1/10;

force = 100 N

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So, Force applied to overcome hydraulic piston is,

1/10 X  100 N

= 10 N