Question

In a hydrogen atom following the Bohr’s postulates the product of linear momentum and angular momentum is proportional to $(n)^{x}$ where ‘n’ is the orbit number. Then ‘x’ is-
(a) 0
(b) 2
(c) –2
(d) 1

Answer 1

x = 0

Solution :

Speed of electron in an orbital nth = v_ n = 2.18 x 10^ 6 Z / n ms^-1

Angular momentum of an orbital nth = L_n = nh / 2π

L_n x mv_n = nh / 2π x m ( 2.18 x 10^ 6 Z / n )

( n ) ^x where n is the orbit number, then:

x = 0