In a hydrogen atom if the energy of electron in the ground state is -Xev then that in the 2nd excited state of he+ is
Answers
Answered by
0
Answer:
-X/9ev
Explanation:
Given the energy in ground state = -Xev
We know that Energy in nth state is given by = E = -13.6*z²÷n²
a) Second excited state = n = 3
b) z = atomic number = 1 for hydrogen
putting the value we get
E = -13.6*1/9 = -13.6*1 * 1/9 ⇒ GIVEN E1=-Xev
using the relation = E = -X/9ev
#SPJ3
Answered by
0
Answer:
-4/9Xev
Explanation:
Given the energy in ground state = -Xev
We know that Energy in nth state is given by = E = -13.6*z²÷n²
a) Second excited state = n = 3
b) z = atomic number = 2 for helium
Excited state 2
Putting the value we get
E = -13.6*1/9 = -13.6*1 * 4/9
using the relation = E = -4/9Xev
#SPJ3
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