Question

In a hydrogen atom if the energy of electron in the ground state is -Xev then that in the 2nd excited state of he+ is

Answer 1

Answer:

-X/9ev

Explanation:

Given the energy in ground state = -Xev

We know that Energy in nth state is given by = E = -13.6*z²÷n²

a) Second excited state = n = 3

b) z =  atomic number = 1 for hydrogen

putting the value we get

E = -13.6*1/9 = -13.6*1 * 1/9 ⇒ GIVEN E1=-Xev

using the relation = E = -X/9ev

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Answer 2

Answer:

-4/9Xev

Explanation:

Given the energy in ground state = -Xev

We know that Energy in nth state is given by = E = -13.6*z²÷n²

a) Second excited state = n = 3

b) z =  atomic number = 2 for helium

Excited state 2

Putting the value we get

E = -13.6*1/9 = -13.6*1 * 4/9

using the relation = E = -4/9Xev

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