Question

In a hydrogen atom the electron and proton are at a distance of 0.5 angstroms . The dipole moment of the system is

Answer 1

Explanation:

dipole moment p=q.2a

where, q=charge

2a=distace between two charges

thus,

for electron and proton charge q=1.6×10^-19c

distance 2a=0.5*10^-10m

therefor p= 1.6×10^-19*0.5*10^-10

p=0.8*10^-29

Answer 2

Given,

Distance between electron and proton 0.5angstorms

To Find,

Dipole moment of the system.

Solution,

We know that dipole moment,

p=q.2a

where, q=charge

2a=distance between two charges

As we know,

For electron and proton charge q=1.6×10^-19c

Distance 2a=0.5*10^-10m

Therefore,

p= 1.6×10^-19×0.5×10^-10

p=0.8×10^-29m

Hence, the dipole moment of the system is 0.8×10^-29m.