Chemistry, asked by Anonymous, 8 months ago

. In a hydrogen atom, the electrons fall from fifth orbit to the second orbit. Calculate the frequency and wavelength of the radiation emitted in this radiation. (Value of R = 109714 cm-1).

Answers

Answered by swapnilsarje17

0

Answer:Wavelength of photon emitted due to electronic transition from n1=3 to n2=2 of hydrogen atom

λ1=R(n221−n121)

∴ λ1=R(221−321) ⟹λ=5R36

Thus frequency of photon ν=λC=365RC

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