In a kilometer race, a beats b by 100 meters. b beats c by 100 meters. by how much meters does a beat c in the same race ?
a. 200 meters
c. 190 meters
b. 180 meters
d. 210 meters
Answers
Answered by
42
Hi ,
A : B = 1000 : 900
B : C = 1000 : 900
(A/B)×(B/C) = (1000/900)(1000/900)
A/C = 100/81
= ( 100/81 ) × ( 10/10 )
= 1000/810
Now ,
A beats C = 1000 - 810
= 190 m
Option ( C ) is correct.
I hope this helps you.
: )
A : B = 1000 : 900
B : C = 1000 : 900
(A/B)×(B/C) = (1000/900)(1000/900)
A/C = 100/81
= ( 100/81 ) × ( 10/10 )
= 1000/810
Now ,
A beats C = 1000 - 810
= 190 m
Option ( C ) is correct.
I hope this helps you.
: )
Answered by
12
Answer:
190 meters
Step-by-step explanation:
time is same in both cases. Hence, ratio of speed is same as that of distance
=> speed(A) : speed(B)= 10:9. similarly, speed(B):speed(C)=10:9
=> A:B:C=100:90:81
in a 1000 meter race A will beat C by 10*(100-81)=190 meters
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