Math, asked by ttgarg1936, 1 year ago

In a kilometer race, a beats b by 100 meters. b beats c by 100 meters. by how much meters does a beat c in the same race ?
a. 200 meters
c. 190 meters
b. 180 meters
d. 210 meters

Answers

Answered by mysticd
42
Hi ,

A : B = 1000 : 900

B : C = 1000 : 900

(A/B)×(B/C) = (1000/900)(1000/900)

A/C = 100/81

= ( 100/81 ) × ( 10/10 )

= 1000/810

Now ,

A beats C = 1000 - 810

= 190 m

Option ( C ) is correct.

I hope this helps you.

: )
Answered by vipulvip1008pedqz1
12

Answer:

190 meters

Step-by-step explanation:

time is same in both cases. Hence, ratio of speed is same as that of distance

=> speed(A) : speed(B)= 10:9. similarly, speed(B):speed(C)=10:9

=> A:B:C=100:90:81

in a 1000 meter race A will beat C by 10*(100-81)=190 meters

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