Question

in a kinetic energy if the velocity increases from V to 2V, 2v to 3v as well as mass increase from m to 2m, 2m to 3m find the ratio of its kinetic energy K.E =1/2mv2

Answer 1

kinetic energy1/2mv2where velocity for 1st is 2v and velocity for 2nd is 3v .Now masses for 1st is 2m and for 2nd is 3m .1st step 1/2mv2 1/22×2×2 =8/2 =4 .Now 2nd step 1/2mv2 1/23×3×3 =27/2 =13.5 answer is 4 : 13.5 .