Question

in a laboratory the count of bacteria in a certain experiment was increasing at the rate of 2.5% per hour. Find the bacteria at the end of 2 hours if the count was initially 506000.

Answer 1

let bacteria=x it was increasing=2.5% so bacteria=x+25÷100 x=x+25÷100 x÷100=x+25 100-25=x×x 75=(x)2 x=8.6602540378 bacteria incresing in 2 hours=2×8.6602540378 =17.3205080757