Question

in a laboratory The Count of bacteria in a certain experiment was increasing at rate 2.5 % per hour find the bacteria at the end of 2 hour if the count was entirely 15600

Answer 1

Rate of increase = 2.5% per hour

Bacteria after 2 hours =

$= 15600 \big(1 + \frac{2.5}{100} \big)^{2} \\ \\ = 15600(1 + 0.025) ^{2} \\ \\ = 15600(1.025) ^{2} \\ \\ = 17335$

Answer 2

Rate of increase = 2.5%per hrs

After 2 hrs

15600(1 2.5/100)^2

15600(1+0.025)^2

15600(1.025)^2

17335