In a laboratory, the count of bacteria in a certain experiment was increasing at the rate of 2.5 % per hour. Find the bacteria at theend of 2 hours if the count was initially 506000.
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in one hour = 2.5%
in two hour =2.5×2=5%
So , bacteria at the end of two hrs= 506000+5% of 506000
506000+25300 = 531300
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