Question

The number of faradays required to reduce 4 g equivalent of cu2+ to cu metal will be :

Answer 1

1 F = charge on 1 mole e-
charge required for 1 geq = 1F
hence 4F charge required.

Hence 4 Faradays would be required to reduce 4g equivalent of cu2+ to Cu metal.

Answer 2

The number of faradays required to reduce 4 g equivalent of $Cu^{2+}$ to Cu metal will be 4

Explanation:

According to mole concept:

1 mole of an atom contains $6.022\times 10^{23}$ number of particles.

We know that:

Charge on 1 electron = $1.6\times 10^{-19}C$

Charge on 1 mole of electrons = $1.6\times 10^{-19}\times 6.022\times 10^{23}=96500C=1F$      (96500C=1Faraday)

$Q=I\times t$

where Q= quantity of electricity in coloumbs

I = current in amperes

t= time in seconds

$Cu^{2+}+2e^-\rightarrow Cu$

2 g equivalent of $Cu^{2+}$ requires 2 Faraday of electricity

4 g equivalent of $Cu^{2+}$ requires =$\frac{2}{2}\times 4geq=4$ Faraday of electricity  

(1 Faraday = 96500 Coloumb)  

Learn More about Faradays first law

https://brainly.in/question/10513111

https://brainly.in/question/6464143