in a labotary the count of bacteria in a certain experiment was increasing at the rate of 2.5 percent per hour find the bacteria at the end of 2 hours if the count was intially 506000
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count of bacteria in the test =506000
rate of bacteria increasing 2.5%
hours=2 hours
2x2.5
=5
506000x5/100=25300
506000
+ 25300
=531300
so answer is 531300
rate of bacteria increasing 2.5%
hours=2 hours
2x2.5
=5
506000x5/100=25300
506000
+ 25300
=531300
so answer is 531300
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