Computer Science, asked by shifastudy7074, 1 year ago

In a leaky bucket used to control liquid flow, how many gallons of liquid are left in the bucket if the output rate is 5 gal/min, there is an input burst of 100 gal/min for 12 s, and there is no input for 48 s?

Answers

Answered by maryamkincsem
16

The input is 100 gal/min, will be 100/60 = 1.667 gal/sec and 1.667*12 =20 gal in 12 seconds.


The output is 5 gal/min, will be 5/60 = 0.08333 gal/sec


As input continues for 12 seconds, 0.8333 * 12 = 1 gallon will be loss in 12s and 0.8333*48 =4 gallon in 48 second.



1+5 gallon in 1 minute and the remaining liquid will be 20-5= 15 gallons after 1 minute. 
Answered by deepikachauhan032
1

Answer:

15 gallons of liquid are left in the bucket after 1 minute.

Explanation:

see the above image for explanation.

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