In a leap year january 26 is friday, what is the day of august 15 in the same year
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First you count all the days from 26 january to 15 august.
Then divide the sum from 7.
Find the remainder.
eg. remainder is 6... then coint 6 days from friday.
Hence answer is thursday.
Then divide the sum from 7.
Find the remainder.
eg. remainder is 6... then coint 6 days from friday.
Hence answer is thursday.
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