In a llgm ABCD , AC and BD intersects at O. If ar(∆AOB)=14.5 cm2,
then ar(llgm ABCD)=_______cm2.
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Answer:
In given figure,
Quadrilateral ABCD is a parallelogram.
So, AD ∣∣ BC
∴ ∠DAC = ∠ACB --- ( Alternate angle)
∴ ∠ACB = 32
∘
∠AOB + ∠BOC = 180
∘
--- (straight angle)
⇒70
∘
+ ∠BOC = 180
∘
∴ ∠BOC = 110
∘
In △BOC,
∠OBC + ∠BOC + ∠OCB = 180
∘
⇒∠OBC + 110
∘
+ 32
∘
= 180
∘
⇒ ∠OBC = 38
∘
∴ ∠DBC = 38
∘
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