Question

In a ∆, LM = 6cm,<=900
, <=and sin=3/5.find the area of
∆.​

Answer 1

Answer:

8th mean = 9 th term in A.P =t

9

=3+8d

(n-2)th mean = (n-1)th term in A.P =t

(n−1)

=3+(n−2)d

It is given that,

t

n−1

t

9

=

5

3

3+(n−2)d

3+8d

=

5

3

9+3nd−6d=15+40d