Question

prove that s=ut +1/2at² graphically​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Hope it helps you

Explanation:

Second equation of motion.

Suppose a body has initial velocity u at point A and this velocity changes to v at point B in t secs.

So, The final velocity will be v.

We need to calculate the distance covered by the object

Using diagram

s=\text{Area of OABC}s=Area of OABC

s=\text{Area of OADC}+\text{Area of ABD}s=Area of OADC+Area of ABD

s=OA\times AD+\dfrac{1}{2}\times AD\times BDs=OA×AD+

2

1

×AD×BD

Put the value into the formula

s=u\times t+\dfrac{1}{2}\times(v-u)s=u×t+

2

1

×(v−u)

We know that,

v=u+atv=u+at

a=\dfrac{v-u}{t}a=

t

v−u

Put the value of (v-u) from first equation of motion

s=ut+\dfrac{1}{2}\times at^2s=ut+

2

1

×at

2