Math, asked by ranjaykumargmo9310, 1 year ago

In a lottery of 50 tickets numbered 1 to 50, one ticket is drawn. find probabiltiy that the ticket drawn bears a prime numbers

Answers

Answered by RishabhRDX
138
Prime number upto 50 = 2,3,5,7,11,13,17,19,23,29,31,37,41,43 and 47

Number of primes= 15
Total numbers= 50
P(prime) = 15/50 = 3/10 or 0.3
Answered by DelcieRiveria
41

Answer:

The probability of getting prime number is 0.3.

Step-by-step explanation:

Total number of tickets is 50.

The prime number between 1 to 50 are 2,3,5,7,11,13,17,19,23,29,31,37,41,43 and 47. The count of prime number between 1 to 50 is 15.

Probability that the ticket drawn bears a prime numbers is

P=\frac{\text{Count of prime number between 1 to 50}}{\text{Total number of tickets}}

P=\frac{15}{50}

P=\frac{3}{10}

P=0.3

Therefore the probability of getting prime number is 0.3.

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