Question

In a mathematics test given to 15 students recorded as 41,39,48,52,46,62,54,40,96,52,98,40,42,52,60 find the mean,median and mode

Answer 1

Answer:

Mean: 54.3

Median: 48

Mode: 40, 52

Step-by-step explanation:

39, 40, 40, 41, 42, 45, 46, 48, 52, 52, 54, 60, 62, 96, 98

Set out the numbers in order.

You can find the mean by adding all of the numbers together, and dividing them by how many numbers you added together. In this case:

(39 + 40 + 40 + 41 + 42 + 45 + 46 + 48+ 52 + 52 + 54 + 60 + 62 + 96 + 98) = 815

There are 15 numbers, and 815/15 = 54.3

You can find the median when you organize the numbers. The median is the middle term in the arranged data set, in this case, 48

The mode is just the most common number. In this instance, there are two modes, because both 40 and 52 are in there twice.

Answer 2

Step-by-step explanation:

Mean=sum of all observation/total no of observation

41+39+48+52+46+62+54+40+96+52+98+40+42+52+60/15

822/15

54.8

media= (n/2+1)

15/2+1

16/2

8th term

40

mode=52