Question

in a maths test 15 students following marks were recorded .41,38, 48,52,46,62,40,96,52,98,40,42,52,60 .find mean ,mode ,median

Answer 1

Answer:

Mean = 767 / 14 ≈ 54.8 (approx)

Median = 50

Mode = 52

Step-by-step explanation:

In preparation for finding the median and mode, it is best to sort the scores first.  Sorted, they are:

38, 40, 40, 41, 42, 46, 48, 52, 52, 52, 60, 62, 96, 98

Now we can see easily that 52 is the most frequent value, turning up 3 times.  So 52 is the mode.

Next, there are 14 values, so the middle two are the 14/2 = 7th and 8th values, which are 48 and 52.  For the median, we take the average of these two middle values, so the median is (48+52)/2 = 50.

The mean is just the sum of the values divided by how many there are.  So the mean is

(38+40+40+41+42+46+48+52+52+52+60+62+96+98) / 14

= 767 / 14

≈ 54.8