Math, asked by gayanajinde05792, 11 months ago

In a meeting 2/9th of those who were present were spinster, 22 were married men, 1/5th Bachelors, 1/3rd married women, how many present at meeting

Answers

Answered by azizalasha
0

Answer:

90

Step-by-step explanation:

2/9 + 1/5 + 1/3 = 34/45

11T/45 = 22

T = 90

Total = 90

Answered by sharonr
0

90 people were present at the meeting

Solution:

According to the question , the number of people in meeting are as follows:

Spinster = \frac{2}{9} th of those who were present

married men = 22

Bachelors = \frac{1}{5} th

Married women = \frac{1}{3} rd

Let the Number of people in the meeting be "x", then from above information:

Total number of people "x" = numner of spinster + married men + bachelors + married women

\begin{array}{l}{\left.x=\left(\frac{2}{9} \times x\right)+22+\left(\frac{1}{5} \times x\right)+\frac{1}{3} \times x\right)} \\\\ {x=\frac{10 x+22 \times 45+9 x+15 x}{45}} \\\\ {x=\frac{34 x+990}{45}} \\\\ {45 x=34 x+990} \\\\ {11 x=990} \\\\ {x=90}\end{array}

Hence total 90 people were present at the meeting

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