Question

In a metallic sheet of 10 cm radius there is a small hole at the centre of the sheet of 3 cm radius. Find the area of the metallic sheet.​

Answer 1

Answer:

Step-by-step explanation:

Area of metal sheet= area of big circle - area of small hole ie. A circle

=πR2-πr2

=22/7×10×10-22/7×3×3

=314.159-28.27

=285.884(answer)

Answer 2

Area of metallic sheet is 286 $cm^{2}$

Step-by-step explanation:

1. Larger radius of sheet (R) =10 cm

  Smaller (hole) radius of sheet (r)= 3 cm

2. Area of larger sheet $\mathbf{(A_{o})=\pi R^{2}}$      ...1)

   Area of hole $\mathbf{(A_{h})=\pi r^{2}}$        ...2)

3. Area of metallic sheet = Area of larger sheet - Area of hole

  Area of metallic sheet $\mathbf{=\pi R^{2}-\pi r^{2}}$

   Area of metallic sheet$\mathbf{=\pi (R^{2}- r^{2})}$     (where $\mathbf{\pi =\frac{22}{7}}$ )

    On putting respective value

    Area of metallic sheet$\mathbf{=\frac{22}{7}(10^{2}- 3^{2})}$

   

    Area of metallic sheet$\mathbf{=\frac{22}{7}\times 91=286 \ cm^{2}}$