Question

In a metre bridge experiment, resistance box (with R = 2Ω ) is connected in the left gap and the unknown resistance S in the right gap. If balancing length be 40 cm, calculate value of S​

Answer 1

Answer:

correct answer is 3 ohm

Answer 2

Answer:

For the unknown resistance the value for S is  $S=3 \mathrm{ohm}$

Explanation:

In the metre bridge experiment, the wheat bridge is used to demonstrate the resistance of an unknown conductor or to compare two unknown resistors.

In the left gap, a resistance box with $2 \Omega$ is attached, and in the right gap, an unknown resistance S.

Balancing length is $40 cm.$

For a BALANCED WHEATSTONE BRIDGE, we know that:

$\frac{R}{S}=\frac{L}{100-L}$

Here, $R$ is known resistance, $S$ is unknown resistance and $L$ is balancing length.

$\begin{aligned}&\frac{2}{S}=\frac{40}{100-40} \\&\frac{2}{S}=\frac{40}{60} \\&\frac{2}{S}=\frac{2}{3} \\&2 S=6 \\&S=3 \mathrm{ohm}\end{aligned}$

The value of $S=3 \mathrm{ohm}$