in a military camp there was sufficient food for 50 days for 200 soldiers. after 10 days 50 new soldiers joined the camp. for how many days the remaining food will last?
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Answered by
0
32 days the remaining food will last.
according to question
there was sufficient food for 50 days for 200soldiers.and after 10 it becomes 250
so,soldiers=200. 250
days=40 x
200×40/250=32 days
mark as brainliest if you got help plz
according to question
there was sufficient food for 50 days for 200soldiers.and after 10 it becomes 250
so,soldiers=200. 250
days=40 x
200×40/250=32 days
mark as brainliest if you got help plz
Answered by
0
The days up to which food will last is 32 days.
Given:
Total number of soldiers = 200
Days till food will last = 50
Total number of new soldiers = 50
Days after which they joined = 10
To Find:
For how many days the remaining food will last?
Solution:
Initial soldiers = 200
Additional soldiers = 50
Therefore, total soldiers-
= 200 + 50
= 250
The food lasted for 50 days, days after which they joined were 10,
Thus, the remaining days = 50 - 10
= 40
By inverse proportion -
x = 200 × 40 / 250
x = 8000/250
x = 800/25
x = 32
Answer: The days up to which food will last is 32 days.
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