In a mixture of caco3 and caco4 the ratio of caco3 to caco4 molecules is 7:5. If there are 35 billion molecules of caco4. How many total molecules are there in the mixture.
Answers
Answered by
4
Answer:
x be the no. of caco 3molecule
caco 3: Caco 4=7:5
7:5::x:35
x = 35x7/5=49
No. of molecules of caco 3 = 49
Total molecules =35+49=84
Answered by
1
In a mixture of caco 3 and caco 4 the ratio of caco 3 to caco 4 molecules is 7:5. If there are 35 billion molecules of caco 4. How many total molecules are there in the mixture.
Answer:
formula is
Can Co 3
40.08 + 12.01 + 16.00(3) =
1000.09 2) mo/
Step-by-step
given I'm my book this answer but this question was different
Given mass = 50 g
Molecular weight of CaCO3 = 100 g / mol
No. of moles (n) = Given mass (m) / Molecular weight (M)
n = 50 / 100
n = 1 / 2
n = 0.5
No. of molecules = n * 6.022 * 10²³
= 0.5 * 6.022 * 10²³
= 3.011 * 10²³
No. of atoms = 5 * 3.011 * 10²³
= 15.055 * 10²³
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