Math, asked by Atitheebnkr, 10 months ago

In a mixture of caco3 and caco4 the ratio of caco3 to caco4 molecules is 7:5. If there are 35 billion molecules of caco4. How many total molecules are there in the mixture.​

Answers

Answered by haridasan85
4

Answer:

x be the no. of caco 3molecule

caco 3: Caco 4=7:5

7:5::x:35

x = 35x7/5=49

No. of molecules of caco 3 = 49

Total molecules =35+49=84

Answered by eshika21
1

In a mixture of caco 3 and caco 4 the ratio of caco 3 to caco 4 molecules is 7:5. If there are 35 billion molecules of caco 4. How many total molecules are there in the mixture.

Answer:

formula is

Can Co 3

40.08 + 12.01 + 16.00(3) =

1000.09 2) mo/

Step-by-step

given I'm my book this answer but this question was different

Given mass = 50 g

Molecular weight of CaCO3 = 100 g / mol

No. of moles (n) = Given mass (m) / Molecular weight (M)

n = 50 / 100

n = 1 / 2

n = 0.5

No. of molecules = n * 6.022 * 10²³

= 0.5 * 6.022 * 10²³

= 3.011 * 10²³

No. of atoms = 5 * 3.011 * 10²³

= 15.055 * 10²³

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