In a mixture of equal weights of h2 and he gases at pressure of 6 atm the partial pressure of helim is
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Answer:
The partial pressure of hydrogen in the mixture of 1.22 atm
Explanation:
We know that partial pressure of a gas is the product of the “total pressure” and the concentration or the “mole fraction of a gas” in the mixture.
Partial pressure = Total pressure × Mole fraction
Let the moles of each gas be X.
We know that the atomic masses given below:
So, we have the mole fraction of each gas which is given below:
The total moles of the gas mixture
Now, to calculate the partial pressure of :
Partial pressure = Total pressure × Mole fraction
Partial pressure = 1.22 atm
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Explanation:
The partial pressure of hydrogen in the mixture of 1.22 atm
Explanation:
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