Chemistry, asked by abhijeetchauha9040, 9 months ago

In a mixture of equal weights of h2 and he gases at pressure of 6 atm the partial pressure of helim is

Answers

Answered by kunal6696
3

Answer:

The partial pressure of hydrogen in the mixture of 1.22 atm

Explanation:

We know that partial pressure of a gas is the product of the “total pressure” and the concentration or the “mole fraction of a gas” in the mixture.

Partial pressure = Total pressure × Mole fraction

Let the moles of each gas be X.

We know that the atomic masses given below:

So, we have the mole fraction of each gas which is given below:

The total moles of the gas mixture

Now, to calculate the partial pressure of :

Partial pressure = Total pressure × Mole fraction

Partial pressure = 1.22 atm

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Explanation:

The partial pressure of hydrogen in the mixture of 1.22 atm

Explanation:

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