Question

in a mixture the amount of zinc is 45% . Find the amt of zinc in 400 g of mixture

Answer 1

Given :

Amount of zinc is 45%

mass of the mixture is 400 g

To Find :

Amount of zinc in 400 g of mixture

Solution :

Amount of zinc = 45%

mass of the mixture = 400 g

Amount of zinc in that mixture =  45% of 400

                                                  =  $\frac{45}{100}$ * 400

                                                  = 45 * 4

                                                  = 180 g

∴ The mixture contains 180 g of Zinc.

Answer 2

Given:

Total mass of mixture = 400 grams

Amount of Zinc in mixture = 45%

To Find: Amount of zinc in mixture grams

Calculation:

Mass amount of zinc in the given mixture = 45% of 400 gm

Mass amount of zinc in the given mixture = $\frac{45}{100} *400 = 180$gm

Answer:

Amount of zinc in grams in the mixture = 180 gm.