`In a mohr titration of chloride with silver nitrate an error is made in the preparation of the indicator. Instead of 0.0011 M chromate indicator in the titration flask at the end point, there is only 0.0011 M. If the flask contains 100 mL at the end point, what is the error in the titrations in milliliters of 0.100 M titrant? Neglect errors due to the color of the solution.'
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Explanation:
Initial speed of the bodies u=0.
Distance covered by the first body in t=3 s, S
1
=ut+
2
1
gt
2
Or S
1
=0+
2
1
×9.8×3
2
=44.1 m
Distance covered by the second body in t
′
=2 s, S
2
=ut
′
+
2
1
g(t
′
)
2
Or S
2
=0+
2
1
×9.8×2
2
=19.6 m
Thus distance between the bodies ΔS=S
1
−S
2
∴ ΔS=44.1−19.6=24.5 m
Solve any question of Motion in a
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