Question

In a money bag, there is ₹ 80
in terms of 50 p coins and ₹1 coins.
If altogether there are 100 coins in thebag find the no. of coins of each type in the bag.​

Answer 1

Step-by-step explanation:

Let No. of coins be x

We are given, x + x/2 = 300

= 3x/2 = 300

so, x = 200

So, there are 200 50p coins as well as 200 1 rupee coins.

Answer 2

$\huge{\blue{\bold{\underline{\underline{Answer :}}}}}$

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$\large\underline{\green{\bf Given :-}}$

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• In a money bag, there were ₹ 80

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• The money is in term of 50 paisa and 1 rupees coins

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• The total number of coins is 100

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$\large\underline{\red{\bf To \: Find :-}}$

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• Number of coins of each type

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$\large\underline{\orange{\bf Solution :-}}$

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• Let 50 paisa coins be "x"

• Let 1 rupees coins be "y"

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$\purple{\underline \bold{According \: to \: the \ question :}}$

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The money is in term of 50 paisa and 1 rupees coins

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$\boxed { 1 \: rupees \: = \: 100 \: paisa }$ $\rm \boxed { 80 \: rupees \: = \: 8000 \: paisa }$

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So,

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➜ 50x + 100y = 8000

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⟮ Dividing the above equation by 50 ⟯

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➜ x + 2y = 160 ⚊⚊⚊⚊ ⓵

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Also given that , the total number of coins is 100

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So,

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➜ x + y = 100 ⚊⚊⚊⚊ ⓶

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⟮ Equation ⓵ - ⓶ ⟯

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➜ x + 2y - (x + y) = 160 - 100

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➜ x + 2y - x - y = 60

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➨ y = 60 ⚊⚊⚊⚊ ⓷

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• Hence total number of 1 rupees coin is 60

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⟮ Putting y = 60 from ⓷ to ⓶ ⟯

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➜ x + y = 100

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➜ x + 60 = 100

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➜ x = 100 - 60

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➨ x = 40

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• Hence total number of 50 paisa coin is 40

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∴ Total number of 50 paisa and 1 rupees coin are 40 & 60 respectively

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