Question

In a morning walk three persons step off together. Their steps
measure 80 cm,85cm and 90 cm respectively. What is the
minimum distance each should walk so that all can cover the
same distance in complete steps?

Answer 1

Answer:

122m 40cm

GIVEN: Their steps measure 80 cm, 85 cm, and 90 cm.

We have to find the L.C.M of the measures of their steps to calculate the required distance each should walk.

L.C.M of 80 cm, 85 cm, and 90 cm.

$80= {2}^{4}×5 \\ 85=17×5 \\ 90=2× {3}^{2} ×5$

$L.C.M(80,85,90)={2}^{4}× {3}^{2} ×5×17 \\ =12240cm$

Hence, the minimum distance each should walk so that all can cover the same distance in complete steps is 12240 cm. or 122m 40cm

Answer 2

Answer:

Now take LCM of 80cm, 85m, 90m.

• 80=2^4×5 , 85= 17×5, 90=2×3^2×5

LCM of (80,85,90)= 2^4×3^2×5×17 = 12240m