Question

in a neutral sphere , 5*10^21 electrons are present. If 10 percent electrons are removed, then calcuilate the charge on sphere

Answer 1

Answer:

10 percent electrons removed i. e. 5 x 1020 electrons removed from sphere.

Total charged on sphere is increase in +ive charge which is equal to decrease in -ve charge,

i.e. (1.6 x 10-19) x (5 x 1020) coulomb