Question

In a new system of units Energy(E),density(d) and Power(P) are taken as the fundamental units then the dimensional formula of universal gravitational constant will be

Answer 1

ML^-1 T^-2....I think so

Answer 2

Answer:

G = E⁻²  D⁻¹  P²

Explanation:

E = [ M  L²  T⁻² ]

P = [ M  L²  T⁻³ ]

D = [ M  L⁻³  T⁰ ]

G = Nm²/Kg²  => [ M⁻¹  L³  T⁻² ]

G = Eᵃ  Dᵇ  Pˣ

Put values of E, D, P

G = [ M  L²  T⁻² ]ᵃ  [ M  L⁻³ ]ᵇ  [ M  L²  T⁻³ ]ˣ

G = [ Mᵃ⁺ᵇ⁺ˣ  L²ᵃ⁻³ᵇ⁺²ˣ  T⁻²ᵃ⁻³ˣ ]

COMPARE

a + b + x = -1

2a - 3b + 2x = 3

-2a -3x = -2

a = -2

b = -1

x = 2

G = [ E⁻²  D⁻¹  P² ]