in a no. of two digits thrice the digit in the units place 1 more than 4 times the digit in the tens place .if the digits are reversed the no formed is 9more than the original no. find the no.
Answers
Answered by
4
Let the no. Be 10a +b
Reversed no. = 10b+a
According to question
3b - 1 = 4a
4a-3b = - 1 -------------------(1)
10a+b + 9 = 10b +a
9a-9b = - 9
a-b = - 1
3a-3b = - 3 -----------------(2)
On subtracting equation 2 from 1,we get
4a-3a = - 1+3
a=2
b = 3
No. = 23
Hope it help you
Please mark as brainliest if you liked the solution
Reversed no. = 10b+a
According to question
3b - 1 = 4a
4a-3b = - 1 -------------------(1)
10a+b + 9 = 10b +a
9a-9b = - 9
a-b = - 1
3a-3b = - 3 -----------------(2)
On subtracting equation 2 from 1,we get
4a-3a = - 1+3
a=2
b = 3
No. = 23
Hope it help you
Please mark as brainliest if you liked the solution
sheikhanser:
brainliest obviously Thanks for the answer
ur welcome
you can ask me any question you want.i will try my best to answer you or any body else
ok
Similar questions