In a non leap year find the probablity of getting 53 tuesday.
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step 1
Possible events for 1 odd day
The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.
step 2
Probability of 1 Odd day to be Tuesday :
The sample space S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}
Expected event of A = {Tuesday}
P(A) =
{Tuesday}
{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}
P(A) = 1/7
P(A) = 0.14
0.14 or 1/7 is probability for 53 Tuesdays in a non-leap year.
srinjan98:
Tnx
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