Math, asked by srinjan98, 1 year ago

In a non leap year find the probablity of getting 53 tuesday.

Answers

Answered by binodkjha1972
2

step 1

Possible events for 1 odd day

The odd day may be either Sunday, Monday, Tuesday, Wednesday, Thursday, Friday or Saturday. Therefore, the total number of possible outcome or elements of sample space is 7.

step 2

Probability of 1 Odd day to be Tuesday :

The sample space S = {Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

Expected event of A = {Tuesday}

P(A) =  

{Tuesday}

{Sunday, Monday, Tuesday, Wednesday, Thursday, Friday, Saturday}

P(A) = 1/7

P(A) = 0.14

0.14 or 1/7 is probability for 53 Tuesdays in a non-leap year.


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