In a non - leap year, what is the probability of 53 Mondays?
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In a non leap year total number of days is 365.
Out of them , there are 52 weeks and one day extra.
Thus,a non leap year always has 52 Mondays. The remaining one day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.
Out of the 7 cases we have Monday in one case.
Total Number of outcomes= 7
Number of favourable outcomes= 1
Probability = Number of favourable outcomes / Total number of outcomes
Required probability (P) = 1/7
Hence, the probability of 53 Mondays= 1/7.
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Out of them , there are 52 weeks and one day extra.
Thus,a non leap year always has 52 Mondays. The remaining one day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.
Out of the 7 cases we have Monday in one case.
Total Number of outcomes= 7
Number of favourable outcomes= 1
Probability = Number of favourable outcomes / Total number of outcomes
Required probability (P) = 1/7
Hence, the probability of 53 Mondays= 1/7.
HOPE THIS WILL HELP YOU...
Answered by
2
Answer:
In a non leap year total number of days is 365.
Out of them , there are 52 weeks and one day extra.
Thus,a non leap year always has 52 Mondays. The remaining one day can be Sunday, Monday, Tuesday, Wednesday, Thursday, Friday and Saturday.
Out of the 7 cases we have Monday in one case.
Total Number of outcomes= 7
Number of favourable outcomes= 1
Probability = Number of favourable outcomes / Total number of outcomes
Required probability (P) = 1/7
Hence, the probability of 53 Mondays= 1/7.
HOPE THIS WILL HELP YOU...
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